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Dimension of magnetic permeability is :...

Dimension of magnetic permeability is :

A

`MLT^(2)A^(-2)`

B

`ML^(-1)T^(-2)A^(-2)`

C

`ML^(-2)T^(-2)A^(2)`

D

`MLT^(-2)A^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Force per unit length between two parallel current carrying wires is given by `(F)/(l) = (mu_(0)I_(1)I_(2))/(2pid)`
`therefore [mu_0] = [(F)/(I^(2))] = [(MLT^(-2))/(A^(2))] = [MLT^(-2)A^(-2)]`
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ALLEN -PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT -EXERCISE-II AIIMS 2010
  1. Dimension of magnetic permeability is :

    Text Solution

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