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If energy (E), velcocity (V) and time (T...

If energy (E), velcocity (V) and time (T) were chosen as fundamental physical quantities for measurement, then the dimensional formula for mass will be

A

`[E^(1) V^(2)T^(1)]`

B

`[E^(2)V^(-2)T^(0)]`

C

`[E^(1)V^(-2)T^(0)]`

D

`[E^(-1)V^(2)T^(1)]`

Text Solution

Verified by Experts

The correct Answer is:
C

`because ` Kinetic energy = `(1)/(2) mV^(2)`
`therefore [m] = [(E)/(V^(2))] = [E^(1)V^(-2)T^(0)]`
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