A body is projected from ground with velocity u making an angle `theta` with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out
(i) angle of projection
(ii) Range and maximum height in terms of u
(iii) ratio of kinetic energy to potential energy of body at maximum height

Answer

(i)`theta=45^(@)`
(ii)`R=(u^(2))/(g),H=(u^(2))/(4g)`
(iii) 1 : 1