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A point moves along a circle with speed ...

A point moves along a circle with speed v=at. The total acceleration of the point at a time when it has traced 1//8th of the circumference is:

A

`(v)/(8a)`

B

`2asqrt(4+pi^(2))`

C

a

D

`(a)/(2)sqrt(4+pi^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
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