Home
Class 12
PHYSICS
A particle of mass 'm' is moving along a...

A particle of mass 'm' is moving along a circle of radius 'r'. At some instant, its speed is 'v' and it is gaining speed at a uniform rate'a', then, at the given instant, acceleration of the mparticle is :

A

along the radius

B

inclined to radius at `theta="sin"^(-1)(1)/([1+(v^(4))/(a^(2)r^(2))]^(1//2))`

C

inclined to radius at `theta=cos^(-1)(ar)/(v^(2))`

D

inclined to radius at `theta=tan^(-1)(v^(2))/(ar)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • RACE

    ALLEN |Exercise Basic Maths (COLLISION AND CENTRE OF MASS )|12 Videos

  • RACE

    ALLEN |Exercise Basic Maths (ROTATIONAL MOTION)|71 Videos

  • RACE

    ALLEN |Exercise Basic Maths (WORK POWER & ENERGY)|33 Videos

  • NEWTONS LAWS OF MOTION

    ALLEN |Exercise EXERCISE-III|28 Videos

  • SIMPLE HARMONIC MOTION

    ALLEN |Exercise Example|1 Videos

Similar Questions

Explore conceptually related problems

A particle is travelling in a circular path of radius 4m . At a certain instant the particle is moving at 20m/s and its acceleration is at an angle of 37^(@) from the direction to the centre of the circle as seen from the particle (i) At what rate is the speed of the particle increasing? (ii) What is the magnitude of the acceleration?

Figure shows the total acceleration and velocity of a particle moving clockwise in a circle of radius 2.5 m at a given instant of time. At this instant, Find: (i) the radial acceleration, (ii) the speed of the particle and (iii) its tangential acceleration.

A particle is moving along a circular path ofradius R in such a way that at any instant magnitude of radial acceleration & tangential acceleration are equal. 1f at t = 0 velocity of particle is V_(0) . Find the speed of the particle after time t=(R )//(2V_(0))

A particle is moving in a circle of radius r with speed v as shown in the figure. The magnitude of change in velocity in moving from P to Q is

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals v_(0) , then th speed of the particle as a function of the distance covered S will be

A particle of mass m is moving with constant speed in a vertical circle in X-Z plane. There is a small both at some distance on Z- axis. The maximum distance of the shadow of the particle on X- axis from origin equal to :-

The magnitude of displacement of a particle moving in a circle of radius a with constant angular speed omega varries with time t is

Assertion:- A particle is moving in a circle with constant tangential acceleration such that its speed v is increasing. Angle made by resultant acceleration of the particle with tangential acceleration increases with time. Reason:- Tangential acceleration =|(dvecv)/(dt)| and centripetal acceleration =(v^(2))/(R)

A car is moving on circular path of radius 100m such that its speed is increasing at the rate of 5m//s^(2) . At t=0 it starts from rest. What is the radial acceleration of car at the instant it makes one complete round trip ?

A point mass moves along a circle of radius R with a constant angular acceleration alpha . How much time is needed after motion begins for the radial acceleration of the point mass to be equal to its tangential acceleration ?