Home
Class 12
PHYSICS
The speed of a particle moving in a circ...

The speed of a particle moving in a circle slows down at a rate of `4 m//sec^(2)`. At some instant the magnitude of the total acceleration is `5 m/sec^(2)` and the particle's speed is 12 m/sec. The radius of circle will be :

A

48

B

30

C

15

D

25

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • RACE

    ALLEN |Exercise Basic Maths (COLLISION AND CENTRE OF MASS )|12 Videos
  • RACE

    ALLEN |Exercise Basic Maths (ROTATIONAL MOTION)|71 Videos
  • RACE

    ALLEN |Exercise Basic Maths (WORK POWER & ENERGY)|33 Videos
  • NEWTONS LAWS OF MOTION

    ALLEN |Exercise EXERCISE-III|28 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN |Exercise Example|1 Videos

Similar Questions

Explore conceptually related problems

Figure shows the total acceleration and velocity of a particle moving clockwise in a circle of radius 2.5 m at a given instant of time. At this instant, Find: (i) the radial acceleration, (ii) the speed of the particle and (iii) its tangential acceleration.

The magnitude of displacement of a particle moving in a circle of radius a with constant angular speed omega varries with time t is

A particle is performing circular motion of radius 1 m. Its speed is v=(2t^(2)) m//s . What will be magnitude of its acceleration at t=1s .

A particle is moving in a circle of radius r with speed v as shown in the figure. The magnitude of change in velocity in moving from P to Q is

A particle is moving along a circular along a circular path of radius 5 m with a uniform speed 5ms^(-1) . What will be the average acceleration when the particle completes half revolution?

The velocity of a particle moving with constant acceleration at an instant t_(0) is 10m//s After 5 seconds of that instant the velocity of the particle is 20m/s. The velocity at 3 second before t_(0) is:-

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to - (K//r^(2)) . Where K is constant. What is the total energy of the particle?

A particle is moving along a circular path ofradius R in such a way that at any instant magnitude of radial acceleration & tangential acceleration are equal. 1f at t = 0 velocity of particle is V_(0) . Find the speed of the particle after time t=(R )//(2V_(0))

A particle starts from rest. Its acceleration at time t=0 is 5 m//s^(2) which varies with time as shown in the figure. The maximum speed of the particle will be

A particle is travelling in a circular path of radius 4m . At a certain instant the particle is moving at 20m/s and its acceleration is at an angle of 37^(@) from the direction to the centre of the circle as seen from the particle (i) At what rate is the speed of the particle increasing? (ii) What is the magnitude of the acceleration?