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Work done in splitting a drop of water o...

Work done in splitting a drop of water of 1 mm radius into 10^6 droplets is (Surface tension of water=`72xx10^(-3)J//m^(2)`)

A

`8.95xx10^(-5)` erg

B

`8.95xx10^(-5)` joule

C

`17.90xx10^(-5)` joule

D

`17.90xx10^(-5)` erg

Text Solution

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The correct Answer is:
B
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