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" If "cos alpha+cos beta=a*sin alpha+sin...

" If "cos alpha+cos beta=a*sin alpha+sin beta=b" and "alpha-beta=2 theta," then "(cos3 theta)/(cos theta)=

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`3x-7y^2+3xyz=3(2)-7(-4)^2+3(2)(-4)(1)`
`=6-7xx16-6xx4`
`=6-112-24`
`=6-136`
`=130`
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