A charge q is placed at the point P as shown in figure on the axis of the ring of elemental thickness 't' and radius R then flux through the ring is :-

Options

A. Zero
B. ` ( q ) / (2sqrt2 epsi _ 0 ) ( sqrt 2 - 1 ) `
C. ` (qt ) /(4sqrt2 epsi _ 0 R ) `
D. ` ( qt ) /( 2 sqrt 2 epsi _ 0 R ) `

Answer

C

Explanation

` d phi =E dS cos theta `
` = ( Kq ) /( 2 R ^ 2 ) ( 2 pi Rt ) ( 1 ) /( sqrt 2 ) `