[" bok of mass "50" kg can slide on a rough horizontal surface.The coefficient of friction between "],[" What and the surfice is "0.6" .The least force of pull acting at an angle of "30^(@)" to the upward drown "],[[" ical which causes the block to just slide is "(g=10" m/sec "^(2)" ) "],[20,03times,(2)219.6N," (3) "21.96N," (4) "294.3N]]

Explanation

To solve the problem, we need to determine the least force \( F \) required to make a block of mass \( 50 \, \text{kg} \) slide on a rough horizontal surface with a coefficient of friction \( \mu = 0.6 \). The force is applied at an angle of \( 30^\circ \) to the horizontal.

### Step-by-Step Solution:

1. **Identify the Forces Acting on the Block:**
- The weight of the block \( W = mg = 50 \, \text{kg} \times 10 \, \text{m/s}^2 = 500 \, \text{N} \).
- The applied force \( F \) has two components:
- Horizontal component: \( F \cos(30^\circ) \)
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