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A particle is revolving in a circle of r...

A particle is revolving in a circle of radius R. If the force acting on it is inversely proportional to R, then the time period is proportional to

A

R

B

`R^(2)`

C

`1//R`

D

`1//R^(2)`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the relationship between the force acting on a particle revolving in a circular path and the time period of its revolution. ### Step-by-Step Solution: 1. **Understanding the Force**: We know that the force acting on the particle is inversely proportional to the radius \( R \). Therefore, we can express this relationship mathematically as: \[ F = \frac{C}{R} \] where \( C \) is a constant. 2. **Centripetal Force**: For a particle of mass \( m \) moving in a circle of radius \( R \) with angular velocity \( \omega \), the centripetal force required to keep the particle in circular motion is given by: \[ F = m R \omega^2 \] 3. **Equating Forces**: Since the force \( F \) acting on the particle is also equal to the centripetal force, we can set the two expressions for \( F \) equal to each other: \[ \frac{C}{R} = m R \omega^2 \] 4. **Rearranging the Equation**: Rearranging the equation gives us: \[ C = m R^2 \omega^2 \] 5. **Solving for Angular Velocity**: From the equation \( C = m R^2 \omega^2 \), we can express \( \omega^2 \) as: \[ \omega^2 = \frac{C}{m R^2} \] 6. **Finding Angular Velocity**: Taking the square root gives us: \[ \omega = \sqrt{\frac{C}{m}} \cdot \frac{1}{R} \] This shows that \( \omega \) is inversely proportional to \( R \): \[ \omega \propto \frac{1}{R} \] 7. **Relating Angular Velocity to Time Period**: The relationship between angular velocity \( \omega \) and the time period \( T \) is given by: \[ \omega = \frac{2\pi}{T} \] Therefore, substituting this into our previous relationship gives: \[ \frac{2\pi}{T} \propto \frac{1}{R} \] 8. **Finding the Time Period**: Rearranging this relationship leads to: \[ T \propto R \] This means that the time period \( T \) is directly proportional to the radius \( R \). ### Conclusion: The time period \( T \) is proportional to the radius \( R \).

To solve the problem, we need to analyze the relationship between the force acting on a particle revolving in a circular path and the time period of its revolution. ### Step-by-Step Solution: 1. **Understanding the Force**: We know that the force acting on the particle is inversely proportional to the radius \( R \). Therefore, we can express this relationship mathematically as: \[ F = \frac{C}{R} ...
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