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The number of Faradays required to depos...

The number of Faradays required to deposit 1g equivalent of aluminium (At. Wt. 27) from a solution of `AlCl_(3)`

A

3

B

1

C

4

D

2

Text Solution

Verified by Experts

The correct Answer is:
A
`Al^(3+) + 3e^(-) to Al`
Therefore , number of electrons required to deposite 1 gm equivelent of aluminium is three mole.
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