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The electronic configuration 1s^(2) 2s^(...

The electronic configuration `1s^(2) 2s^(2) 2p^(5) 3s^(1)` shows

A

ground state of fluorine atom

B

excited state of fluorine atom

C

excited state of neon atom

D

excited state of ion `O_(2)^(-)`

Text Solution

Verified by Experts

The correct Answer is:
C
The ground state electronic configuration of neon atom (Z=10) is :
`1s^(2), 2s^(2), 2p^(6)`
Therefore first excited state of Neon will be :
`1s^(2), 2s^(2), 2p^(5) , 3s^(1)`
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