The coefficient of mutual inductance when magnetic flux change by `4xx10^(-2)Wb` and current changes by `0.01A`, will be

Options

A. 2H
B. 4H
C. 3H
D. 8H

Explanation

To find the coefficient of mutual inductance (M) when the magnetic flux changes by \(4 \times 10^{-2} \, \text{Wb}\) and the current changes by \(0.01 \, \text{A}\), we can use the formula:

\[ M = \frac{d\Phi}{di} \]

where:
- \(d\Phi\) is the change in magnetic flux,
- \(di\) is the change in current.

### Step-by-Step Solution:

1. **Identify the given values:**
- Change in magnetic flux, \(d\Phi = 4 \times 10^{-2} \, \text{Wb}\)
- Change in current, \(di = 0.01 \, \text{A}\)

2. **Substitute the values into the formula:**
\[ M = \frac{d\Phi}{di} = \frac{4 \times 10^{-2} \, \text{Wb}}{0.01 \, \text{A}} \]

3. **Convert the change in current to a more manageable form:**
- \(0.01 \, \text{A} = 1 \times 10^{-2} \, \text{A}\)

4. **Perform the division:**
\[ M = \frac{4 \times 10^{-2}}{1 \times 10^{-2}} = 4 \]

5. **Determine the unit of mutual inductance:**
- The unit of mutual inductance is Henry (H).

6. **Final result:**
\[ M = 4 \, \text{H} \]

### Conclusion:
The coefficient of mutual inductance is \(4 \, \text{H}\).