The weight of one molecules of a compound ` C_(60)H_(122)` is

Options

A. `1.2 xx 10^(-20) ` g
B. `2.025 xx 10^(23) g `
C. `1.4 xx 10^(-21) g `
D. `6.023 xx 10^(23) g `

Explanation

To find the weight of one molecule of the compound \( C_{60}H_{122} \), we can follow these steps:

### Step 1: Calculate the Molecular Weight
First, we need to calculate the molecular weight of the compound \( C_{60}H_{122} \).

1. **Carbon (C)**: There are 60 carbon atoms. The molar mass of carbon is approximately 12 g/mol.
\[ \text{Weight from Carbon} = 60 \times 12 = 720 \text{ g/mol} \]

2. **Hydrogen (H)**: There are 122 hydrogen atoms. The molar mass of hydrogen is approximately 1 g/mol.
\[ \text{Weight from Hydrogen} = 122 \times 1 = 122 \text{ g/mol} \]

3. **Total Molecular Weight**:
\[ \text{Molecular Weight of } C_{60}H_{122} = 720 + 122 = 842 \text{ g/mol} \]

### Step 2: Convert Molecular Weight to Weight of One Molecule
Now, we know that 1 mole of any substance contains \( 6.022 \times 10^{23} \) molecules (Avogadro's number).

4. **Weight of One Molecule**:
\[ \text{Weight of One Molecule} = \frac{\text{Molecular Weight}}{\text{Avogadro's Number}} = \frac{842 \text{ g/mol}}{6.022 \times 10^{23} \text{ molecules/mol}} \]

### Step 3: Perform the Calculation
5. **Calculating the weight**:
\[ \text{Weight of One Molecule} = \frac{842}{6.022 \times 10^{23}} \approx 1.4 \times 10^{-21} \text{ g} \]

### Final Answer
The weight of one molecule of the compound \( C_{60}H_{122} \) is approximately \( 1.4 \times 10^{-21} \) grams.

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