In the reaction : `C_(6)H_(5)CHO+C_(6)H_(5)NH_(2) to C_(6)H_(5)N=HC C_(6)H_(5)+H_(2)O`, the compound `C_(6)H_(5)N =HC C_(6)H_(5)` is known as

Options

A. aldol
B. Schiff's base
C. Schiff's reagent
D. Benedict's reagent .

Explanation

To solve the question, we need to analyze the reaction provided and identify the compound formed.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in the reaction are:
- C₆H₅CHO (which is benzaldehyde, an aldehyde)
- C₆H₅NH₂ (which is aniline, an amine)

2. **Understand the Reaction**:
The reaction can be summarized as:
\[ \text{C}_6\text{H}_5\text{CHO} + \text{C}_6\text{H}_5\text{NH}_2 \rightarrow \text{C}_6\text{H}_5\text{N}=\text{C}\text{H}\text{C}_6\text{H}_5 + \text{H}_2\text{O} \]
Here, the aldehyde (benzaldehyde) reacts with the amine (aniline) to form a compound with a double bond between nitrogen and carbon, releasing water.

3. **Identify the Product**:
The product formed is:
- C₆H₅N=CHC₆H₅, which contains a nitrogen atom double-bonded to a carbon atom that is also bonded to a phenyl group (C₆H₅).

4. **Name the Product**:
The compound C₆H₅N=CHC₆H₅ is known as **Schiff's base**. Schiff's bases are generally formed by the reaction of an amine with an aldehyde or ketone, resulting in the formation of an imine (which contains a C=N bond).

5. **Final Answer**:
Therefore, the compound C₆H₅N=CHC₆H₅ is known as **Schiff's base**.