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The terminal velocity of a sphere of rad...

The terminal velocity of a sphere of radius R, falling in a viscous fluid, is proportional to

A

a.`R^(2)`

B

b.R

C

c.`(1)//(R)`

D

d.`(1)//(R)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Stoke's law:`6piretav=(4)/(3)pir^(3)(rho-sigma)g``therefore V oo r^(2)`As M is given,`rho=(M)/((4)/(3)pir^(3))` but as `r^(3)` increases and `rho` is a constant `sigma` also is a constant.
`therefore` v,the terminal velocity `oo r^(2)`
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