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A 40 mu F capacitor in a defibrillator i...

A 40 `mu F` capacitor in a defibrillator is charged to 3000 V. The energy stored in the capacitor is sent through the patient during a pulse of duration 2ms. The power delivered to the patient is

A

45KW

B

90KW

C

180KW

D

360KW

Text Solution

Verified by Experts

The correct Answer is:
B
The energy stored in capicitor`=(1)/(2)CV^(2)`
`=(1)/(2)xx40xx10^(-6)=180 J`.
`=20xx9xx10^(6)xx10^(-6)=180 J`.
The power delivered in 2 ms is
`=(180)/(2xx10^(-3))=90xx10^(3)` W=90 kW.
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