Home
Class 12
PHYSICS
The cyclotron frequency of an electron m...

The cyclotron frequency of an electron moving in a magnetic field of 1 T is approximately (assume no relativistic effect)

A

28 MHz

B

280 MHz

C

2.8GHz

D

28 GHz

Text Solution

Verified by Experts

The correct Answer is:
D

Cyclotron frequency `v(qB)/(2pim)=(1.6xx10^(-19)xx1)/(2xx3.14xx9.1xx10^(-31))`
`28xx10^(9)Hz=28 GHz`
Promotional Banner

Similar Questions

Explore conceptually related problems

The cyclotron frequency of an electron gyrating in a magnetic field of 1T is approximately:

The acceleration of any electron due to the magnetic fields is

A diamagnetic material in a magnetic field moves

A diamagnetic material in a magnetic field moves

The factor(s) affecting the curvature of the trajectory of an electron moving in a magnetic field is -

(A) : If an electron is not deflected while passing through a certain region of space, then only possibility is that there is no magnetic field in this region (R) : Force on an electron moving in a magnetic field is inversely proportional to the magnetic field applied.

If an electron is moving with velocity v produces a magnetic field vecB , then

Explain the main functions of electric and magnetic fields in a cyclotron.

A proton is accelerating on a cyclotron having oscillating frequency of 11 MHz in external magnetic field of 1 T. If the radius of its dees is 55 cm, then its kinetic energy (in MeV) is is (m_(p)=1.67xx10^(-27)kg, e=1.6xx10^(-19)C)

If an electron is moving in a magnetic field of 5.4 xx 10^(-4)T on a circular path of radius 32 cm having a frequency of 2.5 MHz, then its speed will be