Among the following, the aromatic compound is

Options

A.
B.
C.
D.

Explanation

To determine which of the given compounds is aromatic, we need to follow the criteria for aromaticity. A compound must meet the following conditions:

1. It must be cyclic.
2. It must be planar.
3. It must follow Huckel's rule, which states that the number of π (pi) electrons must equal \(4n + 2\), where \(n\) is a non-negative integer (0, 1, 2, ...).

Let's analyze each option step by step.

### Step 1: Analyze the First Compound
- **Cyclic**: Yes, the compound is cyclic.
- **Planar**: Yes, it is planar.
- **Count π Electrons**: The compound has 2 π electrons.
- Using Huckel's rule: \(4n + 2 = 2\)
- Rearranging gives \(4n = 0\) → \(n = 0\) (valid)

**Conclusion**: The first compound is aromatic.

### Step 2: Analyze the Second Compound
- **Cyclic**: Yes, the compound is cyclic.
- **Planar**: Yes, it is planar.
- **Count π Electrons**: The compound has 4 π electrons.
- Using Huckel's rule: \(4n + 2 = 4\)
- Rearranging gives \(4n = 2\) → \(n = \frac{1}{2}\) (not valid)

**Conclusion**: The second compound is not aromatic.

### Step 3: Analyze the Third Compound
- **Cyclic**: Yes, the compound is cyclic.
- **Planar**: Yes, it is planar.
- **Count π Electrons**: The compound has 4 π electrons.
- Using Huckel's rule: \(4n + 2 = 4\)
- Rearranging gives \(4n = 2\) → \(n = \frac{1}{2}\) (not valid)

**Conclusion**: The third compound is not aromatic.

### Step 4: Analyze the Fourth Compound
- **Cyclic**: Yes, the compound is cyclic.
- **Planar**: Yes, it is planar.
- **Count π Electrons**: The compound has 4 π electrons (2 from the double bond and 2 from the negative charge).
- Using Huckel's rule: \(4n + 2 = 4\)
- Rearranging gives \(4n = 2\) → \(n = \frac{1}{2}\) (not valid)

**Conclusion**: The fourth compound is not aromatic.

### Final Conclusion
Only the first compound satisfies all the criteria for aromaticity. Therefore, the aromatic compound among the given options is:

**Answer**: Option 1 is the aromatic compound.

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