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alpha-Toluic acid in reaction withBr(2)+...

`alpha`-Toluic acid in reaction with`Br_(2)+Fe` gives

A

B

C

D

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To solve the problem of what product is formed when α-Toluic acid reacts with Br₂ and Fe, we can follow these steps: ### Step 1: Identify the structure of α-Toluic acid α-Toluic acid is a benzene ring with a methyl group (–CH₃) and a carboxylic acid group (–COOH) attached to it. The methyl group is ortho- and para-directing, while the carboxylic acid group is meta-directing. ### Step 2: Understand the reaction conditions The reaction involves bromination using Br₂ in the presence of Fe. In this reaction, Br₂ will generate a bromonium ion (Br⁺), which acts as the electrophile. ### Step 3: Determine the directing effects of the substituents - The methyl group (–CH₃) is an electron-donating group and directs electrophilic substitution to the ortho and para positions. - The carboxylic acid group (–COOH) is an electron-withdrawing group and directs electrophilic substitution to the meta position. ### Step 4: Identify the possible positions for bromination Considering the directing effects: - The methyl group can direct bromination to the ortho and para positions. - The carboxylic acid group can direct bromination to the meta position. ### Step 5: Analyze the positions When considering both groups, the only position that satisfies both directing effects is the position that is meta to the carboxylic acid group and ortho to the methyl group. This is because the methyl group prefers ortho and para, but the presence of the carboxylic acid group limits the bromination to the meta position relative to itself. ### Step 6: Draw the product The product will have the bromine atom attached to the carbon that is meta to the carboxylic acid group and ortho to the methyl group. The structure can be represented as follows: - The benzene ring will have: - A methyl group (–CH₃) at one position. - A carboxylic acid group (–COOH) at another position. - A bromine atom (–Br) at the meta position relative to the carboxylic acid group. ### Step 7: Conclusion The final product of the reaction is 3-bromo-α-toluic acid, where the bromine is attached to the carbon that is meta to the carboxylic acid group.
To solve the problem of what product is formed when α-Toluic acid reacts with Br₂ and Fe, we can follow these steps: ### Step 1: Identify the structure of α-Toluic acid α-Toluic acid is a benzene ring with a methyl group (–CH₃) and a carboxylic acid group (–COOH) attached to it. The methyl group is ortho- and para-directing, while the carboxylic acid group is meta-directing. ### Step 2: Understand the reaction conditions The reaction involves bromination using Br₂ in the presence of Fe. In this reaction, Br₂ will generate a bromonium ion (Br⁺), which acts as the electrophile. ...
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