Home
Class 12
CHEMISTRY
For the equilibrium H(2) O (1) hArr H(...

For the equilibrium
`H_(2) O (1) hArr H_(2) O (g)`
at 1 atm `298 K`

A

Standard free energy change is Less than zero `(DeltaGlt0)`

B

standard Free energy change is equal to zero (`DeltaG^(@)=0`)

C

Standard free energy change is greater than zero `(DeltaG^(@>0))`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
B
`H_(2)O_(i)iffH_(2)O_(g)`
This is a spontaneous process at standard conditions thus,the standard free energy change must be less then zero,i.e.,`DeltaG^(@)lt0`.
Promotional Banner

Similar Questions

Explore conceptually related problems

For the equilibrium reaction: 2H_(2)(g) +O_(2)(g) hArr 2H_(2)O(l) at 298 K DeltaG^(Theta) = - 474.78 kJ mol^(-1) . Calculate log K for it. (R = 8.314 J K^(-1)mol^(-1)) .

For a physical equilibrium, H_(2) O (Ice) hArr H_(2) O (Water ) which of the following is the true statement:

For the equilibrium, 2H_(2)O hArr H_(3)O^(+) + OH^(-) ,the value of DeltaG^(@) at 298 K is approximately:

For the equilibrium, 2H_(2)O hArr H_(3)O^(+) + OH^(-) ,the value of DeltaG^(@) at 298 K is approximately:

For the equilibrium H_(2)(g)+CO_(2)(g)hArr hArr H_(2)O(g)+CO(g), K_(c)=16 at 1000 K. If 1.0 mole of CO_(2) and 1.0 mole of H_(2) are taken in a l L flask, the final equilibrium concentration of CO at 1000 K will be

n mole each of H_(2)O(g),H_(2)(g) "and" O_(2)(g) are mixed at a suitable high temperature to attain the equilibrium 2H_(2)O(g)hArr2H_(2)(g)+O_(2)(g) . If y and mole of H_(2)O(g) are the dissociated and the total pressure maintained is P , calculate the K_(P) .

For the vaporisation of water : H_(2)O (I) hArr H_(2)O(g) [1 atm. Pressure] Given : Delta S = 120 JK^(-1) and Delta H =+45.0 kJ . Evaluate the temperature at which liquid water and water vapour are in equilibrium at 1 atm. Pressure-

Consider the following reversible reactionat equilibrium: 2H_(2)O(g) hArr 2H_(2)(g)+O_(2)(g), DeltaH=+24.7 kJ Which one of the following changes in conditions will lead to maximum decomposition of H_(2)O(g) ?

The equilibrium constant for the reaction CO_(2)(g) +H_(2)(g) hArr CO(g) +H_(2)O(g) at 298 K is 73 . Calculate the value of the standard free enegry change (R =8.314 J K^(-1)mol^(-1))

The equilibrium constant for the reaction CO_(2)(g) +H_(2)(g) hArr CO(g) +H_(2)O(g) at 298 K is 73 . Calculate the value of the standard free enegry change (R =8.314 J K^(-1)mol^(-1))