Assertion:The major products formed by heating`C_(6)H_(5)CH_(2)OCH_(3)` with HI are `C_(6)H_(5)CH_(2)l` and `CH_(3)OH`
Reason:Benzyl cation is more stable than methyl cation.

Options

A. If both assertion and reason are true and reason is the explaination of assertion.
B. If both assertion and reason are true but reason is not the correct explaination of assertion
C. If assertion is true but reason is false
D. If both assertion and reason are false.

Explanation

To solve the question, we need to analyze the assertion and reason given.

**Assertion:** The major products formed by heating `C6H5CH2OCH3` with HI are `C6H5CH2I` and `CH3OH`.

**Reason:** Benzyl cation is more stable than methyl cation.

### Step-by-Step Solution:

1. **Identify the Reactants:**
The reactant is `C6H5CH2OCH3`, which is an ether. When heated with HI (hydroiodic acid), we expect a reaction to occur.

2. **Understand the Reaction Mechanism:**
The reaction of ethers with HI typically proceeds via an SN1 mechanism. This involves the formation of a carbocation intermediate.

3. **Carbocation Formation:**
When `C6H5CH2OCH3` is heated with HI, the ether bond can break in two ways:
- The bond between the oxygen and the benzyl group (`C6H5CH2`) can break, leading to the formation of a benzyl carbocation (`C6H5CH2+`).
- The bond between the oxygen and the methyl group (`CH3`) can break, leading to the formation of a methyl carbocation (`CH3+`).

4. **Stability of Carbocations:**
The benzyl carbocation is more stable than the methyl carbocation. This is due to resonance stabilization in the benzyl cation, where the positive charge can be delocalized onto the aromatic ring. In contrast, the methyl cation has no such stabilization.

5. **Product Formation:**
Since the benzyl carbocation is more stable, the reaction will favor the formation of this carbocation. The iodide ion (I-) from HI will then attack the benzyl carbocation to form `C6H5CH2I`. Additionally, the other product formed will be methanol (`CH3OH`), as the methyl group will be protonated and released as a stable molecule.

6. **Conclusion:**
The assertion is correct because the major products are indeed `C6H5CH2I` and `CH3OH`. The reason is also correct, as it explains why the benzyl carbocation is favored over the methyl cation.

### Final Answer:
Both the assertion and reason are correct, and the reason correctly explains the assertion.

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