Home
Class 12
CHEMISTRY
.(92)U^(238) emits 8 alpha- particles an...

`._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus is a)`(62)/(41)` b)`(60)/(41)` c)`(61)/(42)` d)`(62)/(42)`

A

`60//41`

B

`61//40`

C

`62//41`

D

`61//42`

Text Solution

Verified by Experts

The correct Answer is:
C

`""_(92)U^(238)overset(-8alpha)underset(-6beta)rarr""_(82)U^(206)`
Number of protons =82
Number of neutrons = 124
Neutron/proton ratio in the product nucleus `=(124)/(82)=(62)/(41)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A nucleus ._n^ m X emits one alpha- particle and two beta- particles. The resulting nucleus is

A nucleus ._ZX^A emits 9 alpha- particles and 5p particle. The ratio of total protons and neutrons in the final nucleus is.

If ._(92)U^(235) assumed to decay only by emitting two alpha -and one beta -particles, the possible product of decays is

A nucleus ._n X^m emits one alpha and one beta particles. The resulting nucleus is.

._6^12 C absorbs an energenic neutron and emits beta particles. The resulting nucleus is.

A uranium nucleus ._(92)U^(238) emits and alpha -particle and a beta -particle in succession. The atomic number and mass number of the final nucleus will be

If ._92 U^238 undergoes successively 8 alpha- decays and 6 beta- decays, then resulting nucleus is.

When a deuterium is bombarded on ._(8)O^(16) nucleus, an alpha -particle is emitted, then the product nucleus is

If U_92^236 nucleus emits one alpha -particle, the remaining nucleus will have

A nucleus ""_(84)X^(202) of an element emits an alpha particle followed by a beta particle. The final nucleus is ""_(a)Y^(b) . Find a and b.