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For the chemical equilibrium CaCO(3)(s)h...

For the chemical equilibrium `CaCO_(3)(s)hArrCaO(s)+CO_(2)(g),Delta_(r)H^(@)` can be determined from which one of the following plots?

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A
For the reaction,
`CaCO_(3(g))hArrCaO_((g))+CO_(2(g))`
`K_(p)=pco_(2) and K_(C)=[CO_(2)]`
`(because [CaCO_(3)]=1 and [CaO]=1" for solids"]`
According to arrhenius equation we have
`K=Ae^(-Delta H_(r)^(n)//RT)`
Taking logarithm, we have
log `K_(p)=log A-(Delta H_(r)^(@))/(RT(2.303))`
This is an equation of straight line. When log `K_(p)` is plotted against `1//T`. we get a straight line.
The interecept of this line = log A, slope `=-Delta H_(t)^(@)//2.303 R` Knowing the value of slope from the plot and universal gas constant `R,Delta H_(t)^(@)` can be calculated.
(Equation of straight line : `Y=max +C.` Here,
`log K_(p)=-(Delta H_(t)^(@))/(2.303R)((1)/(T))+log A`
`Y" "m" "x" "C`
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