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The major product obtained on treatment ...

The major product obtained on treatment of `CH_(3)CH_(2)CH(F) CH_(3) " with " CH_(3)O^(-)//CH_(3)OH` is :

A

`CH_(3)CH_(2)CH(OCH_(3))CH_(3)`

B

`CH_(3)CH=CHCH_(3)`

C

`CH_(3)CH_(2)CH=CH_(2)`

D

`CH_(3)CH_(2)CH_(2)CH_(2)OCH_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the major product formed when `CH3CH2CHFCH3` is treated with `CH3O^-/CH3OH`. The reaction involves an elimination process, specifically dehydrohalogenation, where a halogen (in this case, fluorine) and a hydrogen atom are removed to form an alkene. ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactant is `CH3CH2CHFCH3`, which is a fluorinated alkane. The base used is `CH3O^-` (methoxide ion) in methanol. 2. **Recognize the Reaction Type**: Since we have a halogen (fluorine) and a base, we can expect an elimination reaction to occur, specifically a dehydrohalogenation reaction. 3. **Determine Possible Elimination Sites**: In the compound `CH3CH2CHFCH3`, we can eliminate the fluorine atom and a hydrogen atom. The hydrogen can be removed from either of the two carbon atoms adjacent to the carbon bearing the fluorine. 4. **Apply Zaitsev's Rule**: According to Zaitsev's rule, the more substituted alkene will be the major product when a non-bulky base is used. We will analyze both possible elimination pathways: - **Pathway 1**: Remove a hydrogen from the carbon next to the fluorine (the second carbon). This leads to the formation of `CH3CH=CHCH3` (butene). - **Pathway 2**: Remove a hydrogen from the terminal carbon (the first carbon). This leads to the formation of `CH3CH2CH=CH2` (butene). 5. **Count the Number of Alpha Hydrogens**: - For the first product (`CH3CH=CHCH3`), there are 6 alpha hydrogens (3 from the first carbon and 3 from the second carbon). - For the second product (`CH3CH2CH=CH2`), there are only 2 alpha hydrogens (2 from the first carbon). 6. **Determine the Major Product**: Since the first product has more alpha hydrogens and is more substituted, it is more stable. Therefore, `CH3CH=CHCH3` is the major product. 7. **Select the Correct Answer**: Among the options provided, the correct answer is `CH3CH=CHCH3`. ### Final Answer: The major product obtained on treatment of `CH3CH2CHFCH3` with `CH3O^-/CH3OH` is `CH3CH=CHCH3`.

To solve the problem, we need to determine the major product formed when `CH3CH2CHFCH3` is treated with `CH3O^-/CH3OH`. The reaction involves an elimination process, specifically dehydrohalogenation, where a halogen (in this case, fluorine) and a hydrogen atom are removed to form an alkene. ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactant is `CH3CH2CHFCH3`, which is a fluorinated alkane. The base used is `CH3O^-` (methoxide ion) in methanol. 2. **Recognize the Reaction Type**: Since we have a halogen (fluorine) and a base, we can expect an elimination reaction to occur, specifically a dehydrohalogenation reaction. ...
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