`CH_(3) CO_(2) C_(2) H_(5)` on reaction with sodium ethoxide in ethanol gives `A`, which on heating in the presence of acid gives `B` compound `B` is

Options

A. `CH_(3)COCH_(2)COOH`
B. `CH_(3)COCH_(3)`
C.
D.

Explanation

To solve the problem, we need to identify the compounds A and B formed in the reactions involving the ester CH₃COOC₂H₅ (ethyl acetate) with sodium ethoxide in ethanol, and then the subsequent reaction of compound A in the presence of acid.

**Step 1: Identify the starting compound.**
The starting compound is given as CH₃COOC₂H₅, which is ethyl acetate.

**Step 2: Reaction with sodium ethoxide.**
When ethyl acetate reacts with sodium ethoxide (C₂H₅ONa) in ethanol, it undergoes a condensation reaction. The sodium ethoxide acts as a base and deprotonates the hydrogen atom adjacent to the carbonyl group of the ester, leading to the formation of a β-keto ester.

The reaction can be represented as follows:
\[ \text{CH}_3COOC_2H_5 + \text{C}_2H_5ONa \rightarrow \text{CH}_3C(OH)(C_2H_5)COOC_2H_5 \]

This compound is labeled as A. The structure of compound A is:
\[ \text{CH}_3C(OH)(C_2H_5)COOC_2H_5 \]

**Step 3: Heating compound A in the presence of acid.**
When compound A is heated in the presence of acid, it undergoes dehydration and rearrangement to form a cyclic compound. The reaction leads to the formation of a compound that has a double bond and a cyclic structure.

The reaction can be represented as follows:
\[ \text{A} \xrightarrow{\text{heat, acid}} \text{B} \]

The structure of compound B can be represented as:
\[ \text{C}_5H_8O_2 \text{ (a cyclic compound)} \]

**Final Answer:**
- Compound A: CH₃C(OH)(C₂H₅)COOC₂H₅
- Compound B: A cyclic compound with a double bond, specifically a compound like 2,5-dimethyl-2,5-dihydrofuran.