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Which of the following diagrams represen...

Which of the following diagrams represent the veriation of electric field vector with time for a circularly polarised light

A

B

C

D

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To solve the question regarding which diagram represents the variation of the electric field vector with time for circularly polarized light, we can follow these steps: ### Step 1: Understand Circularly Polarized Light Circularly polarized light consists of two perpendicular electric field components that are out of phase by 90 degrees (or π/2 radians). These components can be represented as: - \( E_x = E_0 \sin(\omega t) \) - \( E_y = E_0 \sin(\omega t + \frac{\pi}{2}) \) ### Step 2: Express the Second Component Using the trigonometric identity, we can express the second component \( E_y \): - \( E_y = E_0 \sin(\omega t + \frac{\pi}{2}) = E_0 \cos(\omega t) \) ### Step 3: Determine the Resultant Electric Field The resultant electric field vector can be expressed as: - \( \vec{E} = E_x \hat{i} + E_y \hat{j} \) Substituting the expressions we have: - \( \vec{E} = E_0 \sin(\omega t) \hat{i} + E_0 \cos(\omega t) \hat{j} \) ### Step 4: Calculate the Magnitude of the Electric Field The magnitude of the electric field can be calculated as: - \( |\vec{E}| = \sqrt{E_x^2 + E_y^2} \) Substituting the expressions for \( E_x \) and \( E_y \): - \( |\vec{E}| = \sqrt{(E_0 \sin(\omega t))^2 + (E_0 \cos(\omega t))^2} \) - \( |\vec{E}| = E_0 \sqrt{\sin^2(\omega t) + \cos^2(\omega t)} \) ### Step 5: Simplify the Magnitude Using the Pythagorean identity \( \sin^2(\theta) + \cos^2(\theta) = 1 \): - \( |\vec{E}| = E_0 \) ### Step 6: Conclusion The magnitude of the electric field remains constant over time, which indicates that the electric field vector rotates in a circular motion in the plane perpendicular to the direction of propagation of the light. Thus, the correct diagram representing this behavior will show a constant magnitude with a rotating direction. ### Final Answer Based on the analysis, the correct option is **Option A**, which represents the constant magnitude of the electric field vector with time for circularly polarized light. ---

To solve the question regarding which diagram represents the variation of the electric field vector with time for circularly polarized light, we can follow these steps: ### Step 1: Understand Circularly Polarized Light Circularly polarized light consists of two perpendicular electric field components that are out of phase by 90 degrees (or π/2 radians). These components can be represented as: - \( E_x = E_0 \sin(\omega t) \) - \( E_y = E_0 \sin(\omega t + \frac{\pi}{2}) \) ### Step 2: Express the Second Component ...
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