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Circular loop of a wire and a long strai...

Circular loop of a wire and a long straight wire carry current `I_(c )` and `I_(e )`respectively as shown in figure. Assuming that these are placed in the same plane. The magnetic field will be zero at the centre of the loop when the separation `H` is:

A

`(l_(e)R)/(l_(e)pi)`

B

`(l_(e)R)/(l_(e)pi)`

C

`(pil_(e))/(l_(e)R)`

D

`(l_(e)pi)/(l_(e)R)`

Text Solution

Verified by Experts

The correct Answer is:
A

Magnetic field du to a circular loop at the centre of the loop is `B_(1)'=(mu_(0))/(4pi) (2pil_(c))/(R)`
Magnetic field due to a stright line at the centre of the loop is `B_(2)=(mu_(0)2l_(e))/(4piH)`
Both these field act in opposite directio hence total magnetic field at the centre of the loop is
`B=B_(1)-B_(2)=(mu_(2)2pil_(e))/(4pir) -(mu_(0)2l_(e))/(4piH)`
B=0 given
`:. (mu2pil_(e))/(4piR)=(mu_(0)2l_(e))/(4piH) or, H-(l_(e)R)/(pil_(e))`
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