The charge required for reducing 1 mole ...

The charge required for reducing 1 mole of `MnO_4^(-)` to `Mn^(2+)` is

A

1 F

B

3 F

C

5 F

D

6 F

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The correct Answer is:

b

`MnO_(4)^(-)+2H_(2)O+3e^(-) to Mn O_(2)+4OH^(-)` charge required fo the reduction of 1 mol of `MnO_(4)^(-) to MnO_(2)=3F`.

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