Home
Class 12
CHEMISTRY
Which of the following sequence of react...

Which of the following sequence of reaction (reagents) can be used for conversion of `C_(6)H_(5)CH_(2)CH_(3)` into `C_(6)H_(5)CH=CH_(2)` ?

A

`SOCl_(2),H_(2)O`

B

`SO_(2)Cl_(2),alc.KOH`

C

`Cl_(2)//hv,H_(2)O`

D

`SOCl_(2),alc.KOH`

Text Solution

AI Generated Solution

The correct Answer is:
To convert `C6H5CH2CH3` (ethylbenzene) into `C6H5CH=CH2` (styrene), we can follow a sequence of reactions. Here’s a step-by-step breakdown of the process: ### Step 1: Allylic Chlorination - **Reagent**: SO2Cl2 (sulfuryl chloride) - **Reaction**: The first step involves treating ethylbenzene with SO2Cl2. This reagent facilitates allylic chlorination, where a chlorine atom is introduced at the allylic position (the carbon adjacent to the double bond). - **Product**: The product will be `C6H5CHClCH3`, where a chlorine atom replaces one of the hydrogen atoms on the carbon adjacent to the benzene ring. ### Step 2: Elimination Reaction - **Reagent**: Alcoholic KOH (potassium hydroxide in alcohol) - **Reaction**: The next step involves treating the chlorinated product with alcoholic KOH. This step promotes a beta elimination reaction, where the chlorine atom (a good leaving group) is removed along with a hydrogen atom from the adjacent carbon. - **Product**: The result of this elimination will yield `C6H5CH=CH2`, which is styrene. ### Final Reaction Sequence 1. **C6H5CH2CH3 + SO2Cl2 → C6H5CHClCH3** 2. **C6H5CHClCH3 + Alcoholic KOH → C6H5CH=CH2** ### Conclusion The reagents required for the conversion of `C6H5CH2CH3` into `C6H5CH=CH2` are **SO2Cl2 followed by alcoholic KOH**. ---
To convert `C6H5CH2CH3` (ethylbenzene) into `C6H5CH=CH2` (styrene), we can follow a sequence of reactions. Here’s a step-by-step breakdown of the process: ### Step 1: Allylic Chlorination - **Reagent**: SO2Cl2 (sulfuryl chloride) - **Reaction**: The first step involves treating ethylbenzene with SO2Cl2. This reagent facilitates allylic chlorination, where a chlorine atom is introduced at the allylic position (the carbon adjacent to the double bond). - **Product**: The product will be `C6H5CHClCH3`, where a chlorine atom replaces one of the hydrogen atoms on the carbon adjacent to the benzene ring. ### Step 2: Elimination Reaction ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The most appropriate reagent for conversion of C_(2) H_(5) CN into CH_(3) CH_(2) CH_(2) NH_(2) is :

C_(6)H_(5)CONHCH_(3) can be converted into C_(6)H_(5)CH_(2)NHCH_(3) by .

Which of the following reactions can be used to prepare CH_(3)-underset(C_(2)H_(5))underset(|)overset(OH)overset(|)C-C_(6)H_(5)

Which of the following compounds will show cis-trans isomerism? (i) (CH_(3))_2C=CH-C_(2)H_(5) (ii) CH_(2)=CBr_(2) (iii) C_(6)H_(5)CH=CH-CH_(3) CH_(3)CH="CC"lCH_(3)

Which of the following are intermediates in the reaction of excess of CH_(3) MgBr " with" C_(6)H_(5)COOC_(2)H_(5) to make 2 - phenyl -2- propanol ? A. C_(6)H_(5) - overset("OMgBr") overset(|) underset(CH_(3)) B. C_(6)H_(5) - overset(O) overset(||) - CH_(3) C. C_(6)H_(5) - overset("OMgBr") overset(|) underset(CH_(3)) underset(|) C- CH_(3)

Distinction between pairs of compounds Ethanol (CH_(3)CH_(2)OH) and Phenol (C_(6)H_(5)OH)

Arrange compounds in each set according to specified order and give reasons for your answer. Increasing order of solubility in water. C_(6)H_(5)CH_(2)OCH_(3), C_(6)H_(5)CH_(2)CH_(2)CH_(3), p-CH_(3)C_(6)H_(4)COOH, p-OHC_(6)H_(4)CH_(2)OH

Predict the order of reactivity of the compounds in S_(N)1 and S_(N) 2 reactions . C_(6)H_(5)CH_(2) Br, C_(6)H_(5) CH (C_(6)H_(5)) Br , C_(6) H_(5) CH(CH_(3)) Br , C_(6)H_(5) C (CH_(3)) (C_(6)H_(5)) Br

Consider the following carbocations (I) C_(6)H_(5)overset(+)CH_(2) , (II) C_(6)H_(5)CH_(2)overset(+)CH_(2) (III) C_(6)H_(5)overset(+)CHCH_(3) , (IV) C_(6)H_(5)overset(+)C(CH_(3))_(2) The correct sequence for the stability of these is