The major product formed in the following reaction is `CH_(3)CH(Cl)CH_(2)-CH_(2)OHoverset(aq.KOH)to`

Options

A. `CH_(3)CH=CH-CH_(2)OH`
B. `CH_(2)=CH-CH_(2)-CH_(2)OH`
C. `{:(CH_(3)-CH-CH_(2)),(" | |"),(" "O-CH_(2)):}`
D. `CH_(3)-underset(OH)underset(|)CH-CH_(2)-CH_(2)OH`

Explanation

To solve the question regarding the major product formed in the reaction of `CH3CH(Cl)CH2-CH2OH` with aqueous KOH, we will follow these steps:

### Step 1: Identify the Reactant
The reactant is `CH3CH(Cl)CH2-CH2OH`. This compound has a chlorine atom (Cl) attached to the second carbon of a four-carbon chain, along with a hydroxyl group (OH) at the end.

### Step 2: Understand the Reaction Conditions
The reaction is performed in the presence of aqueous KOH. Aqueous KOH provides hydroxide ions (OH-) which can act as nucleophiles.

### Step 3: Mechanism of Reaction
In the presence of aqueous KOH, the hydroxide ion (OH-) will perform a nucleophilic substitution reaction. The Cl atom is a good leaving group, and the OH- will attack the carbon atom bonded to Cl, leading to the substitution of Cl with OH.

### Step 4: Perform the Nucleophilic Substitution
The nucleophilic attack by OH- on the carbon atom bonded to Cl results in the formation of a new bond between the carbon and the hydroxyl group, while the Cl is released as a chloride ion (Cl-). The product formed will be `CH3CH(OH)CH2-CH2OH`.

### Step 5: Identify the Major Product
The product formed from this reaction is a diol, specifically `CH3CH(OH)CH2-CH2OH`, which has two hydroxyl groups. This is the major product of the reaction because nucleophilic substitution is favored in this scenario.

### Step 6: Conclusion
The major product formed in the reaction is `CH3CH(OH)CH2-CH2OH`.

### Final Answer
The major product is `CH3CH(OH)CH2-CH2OH`.

---