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With the decrease of current in the prim...

With the decrease of current in the primary coil from 2 A to zero in 0.01s, the e.m.f. generated in the secondary cail is 1000 V. The mutual inductance of the two coil is

A

1.25 H

B

2.50 H

C

5.00 H

D

10.00 H

Text Solution

Verified by Experts

The correct Answer is:
C
Induced emf `epsilon = (-Mdl_(P))/(dt)`
where M is the mutual inductance of two coils and `(dI_(P))/(dt)` is the rate of change of current in the primary.
`therefore 1000 V = (-M(OA-2A))/(0.01 s)`
or `M = ((1000 V)(0.01 s))/((2 A))=5 H`.
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