Faraday law of electrolysis indirectly shows

Options

A. a.quantisation of charge
B. b.quantisation of angular momentum
C. c.quantisation of current
D. d.quantisation of viscosity

Answer

To solve the question regarding Faraday's law of electrolysis and its implications, we can break it down step by step.

### Step-by-Step Solution:

1. **Understanding Faraday's Law of Electrolysis**:
- Faraday's first law states that the amount of substance deposited or liberated at an electrode during electrolysis is directly proportional to the quantity of electric charge (Q) that passes through the electrode.
- Mathematically, this can be expressed as:
\[ W \propto Q \]
where \( W \) is the mass of the substance deposited or liberated, and \( Q \) is the charge.

2. **Relating Charge to Current and Time**:
- The charge \( Q \) can also be expressed in terms of current \( I \) and time \( t \):
\[ Q = I \times t \]
- Substituting this into the first law gives:
\[ W \propto I \times t \]
- This shows that the amount of substance is dependent on the current and the time for which it flows.

3. **Quantization of Charge**:
- The relationship established by Faraday's law implies that charge is quantized, meaning it exists in discrete amounts (like electrons). This is because the amount of substance deposited can only take specific values based on the charge passed, which is a multiple of elementary charge \( e \).
- Therefore, Faraday's law indirectly supports the concept of quantization of charge.

4. **Evaluating the Options**:
- Given the options:
- A) Quantization of charge
- B) Quantization of angular momentum
- C) Quantization of current
- D) Quantization of viscosity
- From our analysis, we can conclude that the correct answer is **A) Quantization of charge**.

### Final Answer:
The correct option is **A) Quantization of charge**.