Home
Class 12
PHYSICS
In an adiabatic change the pressure and ...

In an adiabatic change the pressure and temperature of monoatomic gas are related as `P prop T^(c )` where C equal

A

`(2)/(5)`

B

`(5)/(2)`

C

`(3)/(5)`

D

`(5)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

`gamma = 1+(2)/(f)`
`rArr gamma` for mono atomic gas `= 1+(2)/(3)=(5)/(3)`
For adiabatic relation `(P^(gamma-1))/(T^(gamma))` = const,
`P prop T^((gamma)/(gamma-1)) rArr P prop T^((5)/(3)xx(3)/(2))`
`therefore T^(C )=T^((5)/(2))rArr C = (5)/(2)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

In an adiabatic change, the pressure p and temperature T of a diatomic gas are related by the relation ppropT^alpha , where alpha equals

An ideal gas undergoing adiabatic change has the following pressure-temperature relationship

For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume TV^(x) = constant, where x is

Some ideal monoatomic gas A in an enclosure has a pressure P and the temperature T . Another ideal monoatomic gas B enclosed in a container of the same volume has a pressure of 2P and temperature T/2 . The ratio of the average kinetic energy per molecule of gas A to gas B is

A monoatomic gas undergoes adiabatic process. Its volume and temperature are related as TV^(P) = constant. The value of p will be {:((1),1.33,(2),1.67),((3),0.67,(4),0.33):}

A monoatomic gas undergoes a process in which the pressure (P) and the volume (V) of the gas are related as PV^(-3)= constant. What will be the molar heat capacity of gas for this process?

On mole of a monoatomic ideal gas is taken through the cycle shown in figure . A rarr B : Adiabatic expansion " " BrarrC : Cooling at constant volume CrarrD : Adiabatic compression " " D rarr A : Heating at constant volume The pressure and temperature at A , B , etc, are denoted by P_(A) , T_(A) , P_(B) , T_(B) etc., respectively . Given that T_(A) = 1000K, P_(B) = ((2)/(3))P_(A)"and"P_(C) = ((1)/(3))P_(A) . Calculate the following quantities: (i) The work done by the gas in the processs A rarr B (ii) The heat lost by the gas in the process B rarr C (iii) The temperature T_(D). ("Given" : ((2)/(3))^(2//5) = 0.85 )

One mole of a monoatomic ideal gas is taken through the cycle shown in Fig: AtoB : adiabatic expansion BtoC : cooling at constant volume CtoD : adiabatic compression DtoA : heating at constant volume The pressure and temperature at A,B,etc. are denoted by P_A, T_A,P_B,T_B etc. respectively. Given that T_A=1000K , P_B=(2//3)P_A and P_C=(1//3)P_A , calculate the following quantities: (i) The work done by the gas in the process AtoB (ii) The heat lost by the gas in the process BtoC . (iii) The temperature T_D . [Given : (2//3)^(2//5)=0.85 ]

One mole of a monoatomic ideal gas is taken through the cycle shown in figure. ArarrB Adiabatic expansion BrarrC Cooling at constant volume CrarrD Adiabatic compression. DrarrA Heating at constant volume The pressure and temperature at A,B etc., are denoted by p_A, T_A, p_B, T_B etc. respectively. Given, T_A=1000K , p_B=(2/3)p_A and p_C=(1/3)p_A . Calculate (a) the work done by the gas in the process ArarrB (b) the heat lost by the gas in the process BrarrC Given, (2/3)^0.4=0.85 and R=8.31J//mol-K