Home
Class 12
PHYSICS
The velocity of electromagnetic radiatio...

The velocity of electromagnetic radiation in a medium of permittivity `epsilon_(0)` and permeability `mu_(0)` is given by:

A

`1/sqrt(mu_0 epsilon_0)`

B

`sqrt((mu_0)/(epsilon_0))`

C

`sqrt((epsilon _0)/(mu_0)`

D

`sqrt(mu_0epsilon_0)`

Text Solution

Verified by Experts

The correct Answer is:
A
Velocity of electromagnetic wave is `e = (1)/(sqrt(mu_(0)epsi_(0)))`
Promotional Banner

Similar Questions

Explore conceptually related problems

On an energy level diagram of hydrogen, show by a downward or an upward arrow, a transition which results in : (i) emission line of Balmer series. (ii) emission line of Lyman series. (iii) absorption line of Lyman series. (b) (i) Define unified atomic mass unit . (ii) Write the expression for speed of electromagnetic waves in a medium of electrical permittivity epsilon and magnetic permeability mu .

The velocity of electromagnetic waves in a dielectric medium (in_(r)=4) is

Express velocity of electromagnetic wave in a material medium in terms of mu and epsi .

In terms of potential difference V , electric current I , permittivity epsilon_(0) , permeability mu_(0) and speed of light c , the dimensionally correct equation (s) is (are)

The unit of permittivity of free space epsilon_(0) is:

The unit of permittivity in free space epsilon_(0) is:

The speed of an electromagnetic wave in a material medium is given by n=(1)/(sqrt(mu epsilon)), m being the permeability of the medium and e its permittivity. How does its frequency change ?

Dimension of resistance R in terms of mu0 & epsilon_(0) are

Assertion : The velocity of electromagnetic waves depends on electric and magnetic properties of the medium Reason : Velocity of electromagnetic waves in free space is constant.

The maximum wavelength of electromagnetic radiation, which can create a hole-electron pair in germanium. (Given that forbidden energy gap in germanium is 0.72 eV)