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What is the correct relationship between the pHs of isomolar solutions of sodium oxide `(pH_(1))`, sodium sulphide `(pH_(2))`, sodium selenide `(pH_(3))` and sodium telluride `(pH_(4))` ?

A

`pH_4 gt pH_2=pH_3=pH_4`

B

`pH_3 le pH_2 le pH_3 le PH_3 `

C

`pH_4 ge pH_2 le pH_2 `

D

`pH_1 gt pH_2 gt pH_3 gt pH_4`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(I , Na_(2)O + H_(2)O to 2 NaOH) , (II , Na_(2)S + H_(2)O to 2NaOH + H_(2)S), (III , Na_(2)Se + H_(2)O to 2 NaOH + H_(2)Se),(IV , Na_(2) Te + H_(2)O to 2NaOH + H_(2)Te):}`
I will have the highest pH , Among `H_(2)S , H_(2) Se , H_(2)` Te acidity goes on increasing on going down the group as bond length increases on increasing size of central atom . So , `pH_(4) lt pH_(3) lt pH_(2)`
Overall order is `pH_(1) gt pH_(2) gt pH_(3) gt pH_(4)`
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