Home
Class 12
CHEMISTRY
A current of 3 ampere has to be passed t...

A current of 3 ampere has to be passed through a solution of `AgNO_(3)` solution to coat a metal surface of `80 cm^(2)` with 0.005 mm thick layer for a duration of approximately `y^(3)` second what is the value of y?
Density of Ag is 10.5 `g//cm^(3)`

A

115 sec

B

124 sec

C

135 sec

D

145 sec

Text Solution

Verified by Experts

The correct Answer is:
B

Weight of Ag required = `V xx d`
`= 80 xx 5 xx 10^(-3) xx 1.05 = 0.42`
`because W = ("Eit")/(96500) `
`therefore 0.42 = (108 xx 3 xx t)/(96500) implies t = 125` sec .
Promotional Banner

Similar Questions

Explore conceptually related problems

How long a current of 2 A has to be passed through a solution of AgNO_(3) to coat a metal surface of 80cm^(2) with 5mum thick layer? Density of water =10.8g//cm^(3)

How long a current of 3A has to be passed through a solution of AgNO_(3) , to coat a metal surface of 80 cm^(2) with 5 mum thick layer? Density of sikver = 10.8 g//cm^(3)

How long a current of 3A has to be passed through a solution of silver nitrate to coat a metal surface of 80cm^(2) with a 0.005-mm- thick layer ? The density of silver is 10.5g cm^(-3) .

For how Iong a current of threc amperes has lu be passed through a solution of AgNO_3 to coat a metal surface of 80cm^2 area with 0.005mm thick layer? Density of silver is 10.6g/cc and atomic weight of Ag is 108 gm/mol.

Calculate the time required to coat a metal surface of 80 cm^(2) with 0.005 mm thick layer of silver (density = 10.5 g cm^(3)) with the passage of 3A current through silver nitrate solution.

A current 0.5 ampere when passed through AgNO_(3) solution for 193 sec. Deposited 0.108 g of Ag. Find the equivalent weight of Ag.

A current of 3 amperes was passed through silver nitrate solution for 125 seconds. The amount of silver deposited at cathode was 0.42 g. Calculate the equivalent mass of silver.

When X amperes of current is passed through molten AlCl_(3) for 96.5 s. 0.09 g of aluminium is deposited. What is the value of X?

108 g solution of AgNO_(3) is electrolysed using Pt electrodes by passing a charge of 0.1 F. The mass of resultant solution left is :

If 103 cm^(3) of aluminium has a mass of 0.280 kg. Find its density in g//cm^(3)