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A rodiactive nucleus is being produced a...

A rodiactive nucleus is being produced at a constant rate `alpha` per second Its decay constant is `lambda` If `N_(0)` are the number of nuclie at tieme t=O then, maximum number of nuclei possible are

A

`N_(0)+(alpha)/(lambda)`

B

`N_(0)`

C

`(lambda)/(alpha)+N_(0)`

D

`(alpha)/(lambda)`

Text Solution

Verified by Experts

The correct Answer is:
D
Maximum number of nuclei will be present, when rate of decay = rate of formation
`lambda. N=alpha, N=(alpha)/(lambda)`
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