Mercurous chloride exists in the form of

Options

A. `Hg^(+)`
B. `Hg_(2)^(2+)`
C. `Hg^(2+)`
D. `Hg_(3)^(2+)`

Answer

To solve the question regarding the form in which mercurous chloride exists, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Chemical Formula**:
- The chemical formula for mercurous chloride is \( \text{Hg}_2\text{Cl}_2 \).

2. **Dissociation of Mercurous Chloride**:
- When mercurous chloride (\( \text{Hg}_2\text{Cl}_2 \)) dissociates in solution, it breaks down into ions. The dissociation can be represented as:
\[ \text{Hg}_2\text{Cl}_2 \rightarrow \text{Hg}_2^{2+} + 2\text{Cl}^- \]
- Here, \( \text{Hg}_2^{2+} \) represents the mercurous ion, and \( \text{Cl}^- \) represents the chloride ions.

3. **Identify the Form of Mercurous Ion**:
- The mercurous ion is denoted as \( \text{Hg}_2^{2+} \). This indicates that two mercury atoms are bonded together and carry a +2 charge.

4. **Evaluate the Given Options**:
- The options provided are:
1. \( \text{Hg}^+ \)
2. \( \text{Hg}_2^{2+} \)
3. \( \text{Hg}^{2+} \)
4. \( \text{Hg}_3^{2+} \)
- From our dissociation, we see that the correct representation of the mercurous ion in mercurous chloride is \( \text{Hg}_2^{2+} \).

5. **Select the Correct Answer**:
- Based on the analysis, the correct answer is option 2: \( \text{Hg}_2^{2+} \).

### Final Answer:
Mercurous chloride exists in the form of \( \text{Hg}_2^{2+} \).

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