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alpha-(D) glucose hArr beta (D) glucose,...

`alpha`-(D) glucose `hArr beta` (D) glucose, equilibrium constant for this is 1.8. The percentage of `alpha`-(D) glucose at equilibrium is

A

35.7

B

64.3

C

55.6

D

44.4

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(,alpha-"D glucose ",hArr,beta-"D glucose"),("Initial",1,,0),("At equilibrium",1-alpha,,alpha):}`
`K=(alpha)/(1-alpha)=1.8`
Soving `alpha=0.642`
`1-alpha=0.358`
Percent of `alpha-D` glucose remaining at equilibrium `=35.8%`.
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