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The M-O-M bond angles in M(2)O (where M ...

The `M-O-M` bond angles in `M_(2)O` (where M is halogen) is in the order

A

`Br_(2)O gt Cl_(2)O gt F_(2)O`

B

`F_(2)O gt Br_(2)O gt Cl_(2)O`

C

`F_(2)O gt Cl_(2)O gt Br_(2)O`

D

`Cl_(2)O gt F_(2)O gt Br_(2)O`

Text Solution

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The correct Answer is:
To determine the order of the M-O-M bond angles in \( M_2O \) (where M is a halogen), we will analyze the structures of \( Br_2O \), \( Cl_2O \), and \( F_2O \) and their respective bond angles. ### Step-by-Step Solution: 1. **Identify the Structures**: - For \( Br_2O \): The structure consists of two bromine atoms bonded to an oxygen atom. Oxygen has two lone pairs. - For \( Cl_2O \): Similar to \( Br_2O \), it has two chlorine atoms bonded to an oxygen atom, with oxygen also having two lone pairs. - For \( F_2O \): This structure has two fluorine atoms bonded to an oxygen atom, with oxygen having two lone pairs. 2. **Analyze the Bond Angles**: - The bond angle in \( Br_2O \) is approximately \( 116^\circ \). - The bond angle in \( Cl_2O \) is around \( 109.5^\circ \) (or \( 109^\circ 28' \)). - The bond angle in \( F_2O \) is about \( 104.5^\circ \) (or \( 105^\circ \)). 3. **Consider the Effects of Atomic Size and Electronegativity**: - The bond angle is influenced by the size of the surrounding halogen atoms and their electronegativity. - As we move down the group in the periodic table from fluorine to bromine, the atomic size increases. Larger atoms (like bromine) create less repulsion between the lone pairs on oxygen and the bonding pairs, leading to larger bond angles. - Fluorine, being the smallest and most electronegative, pulls the bonding electrons closer to itself, increasing lone pair-lone pair repulsion, which results in a smaller bond angle. 4. **Establish the Order**: - Based on the analysis, the order of bond angles from largest to smallest is: \[ Br_2O > Cl_2O > F_2O \] 5. **Conclusion**: - The correct order of the M-O-M bond angles in \( M_2O \) (where M is a halogen) is \( Br_2O > Cl_2O > F_2O \).
To determine the order of the M-O-M bond angles in \( M_2O \) (where M is a halogen), we will analyze the structures of \( Br_2O \), \( Cl_2O \), and \( F_2O \) and their respective bond angles. ### Step-by-Step Solution: 1. **Identify the Structures**: - For \( Br_2O \): The structure consists of two bromine atoms bonded to an oxygen atom. Oxygen has two lone pairs. - For \( Cl_2O \): Similar to \( Br_2O \), it has two chlorine atoms bonded to an oxygen atom, with oxygen also having two lone pairs. - For \( F_2O \): This structure has two fluorine atoms bonded to an oxygen atom, with oxygen having two lone pairs. ...
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