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The position of a particle moving in the...

The position of a particle moving in the xy-plane at any time t is given by `x = (3t^(2) - 6t) m, y = (t^(2) - 2t)m`. Select the correct statement about the moving particle from the following.

A

acceleration is zero at t= 0

B

velocity is zero at t= 0

C

velocity is zero at t=1s

D

velocity and acceleration of the particle are never zero.

Text Solution

Verified by Experts

The correct Answer is:
C

` x = 3 t ^ 2 - 6 t , ` so ( velocity ) `""_x` = ` ( dx ) /( dy ) = 6t - 6 , `
` y = t ^ 2 - 2t `
So, (velocity ) `""_ y ` ` = (dy )/ ( dx ) = 2t - 2 `
At time ` t = 1 `,
` = ( dx ) / (dt ) = 6 xx 1 - 6 = 0 and (dy ) /( dx ) = 2 xx 1 - 2 = 0 `
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