Home
Class 12
PHYSICS
Assertion : If momentum of a body increa...

Assertion : If momentum of a body increases by 50%, its kinetic energy will increase by 125%.
Reason: Kinetic energy is proportional to square of velocity.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze both the assertion and the reason step by step. ### Step 1: Understand the relationship between momentum and kinetic energy. The kinetic energy (E) of a body can be expressed in terms of its momentum (p) as follows: \[ E = \frac{p^2}{2m} \] where \( m \) is the mass of the body. ### Step 2: Determine the new momentum after a 50% increase. If the initial momentum is \( p \), then an increase of 50% means the new momentum \( p' \) is: \[ p' = p + 0.5p = 1.5p \] ### Step 3: Calculate the new kinetic energy using the new momentum. Substituting \( p' \) into the kinetic energy formula: \[ E' = \frac{(p')^2}{2m} = \frac{(1.5p)^2}{2m} = \frac{2.25p^2}{2m} = \frac{2.25}{2} \cdot \frac{p^2}{m} = 1.125 \cdot \frac{p^2}{m} \] ### Step 4: Calculate the initial kinetic energy. The initial kinetic energy \( E \) is: \[ E = \frac{p^2}{2m} \] ### Step 5: Find the change in kinetic energy. The change in kinetic energy \( \Delta E \) is: \[ \Delta E = E' - E = \left(1.125 \cdot \frac{p^2}{m}\right) - \left(\frac{p^2}{2m}\right) \] To express this in terms of the initial kinetic energy: \[ \Delta E = \left(1.125 - 0.5\right) \cdot \frac{p^2}{2m} = 0.625 \cdot \frac{p^2}{2m} \] ### Step 6: Express the new kinetic energy in terms of percentage increase. The new kinetic energy \( E' \) can also be expressed as: \[ E' = E + \Delta E = E + 0.625E = 1.625E \] This means the kinetic energy has increased by: \[ \Delta E = E' - E = 1.625E - E = 0.625E \] Thus, the percentage increase in kinetic energy is: \[ \text{Percentage Increase} = \frac{\Delta E}{E} \times 100 = \frac{0.625E}{E} \times 100 = 62.5\% \] ### Conclusion: The assertion that if momentum increases by 50%, kinetic energy increases by 125% is incorrect. The reason provided is correct as kinetic energy is indeed proportional to the square of velocity. ### Final Answer: - **Assertion**: Incorrect - **Reason**: Correct

To solve the problem, we will analyze both the assertion and the reason step by step. ### Step 1: Understand the relationship between momentum and kinetic energy. The kinetic energy (E) of a body can be expressed in terms of its momentum (p) as follows: \[ E = \frac{p^2}{2m} \] where \( m \) is the mass of the body. ### Step 2: Determine the new momentum after a 50% increase. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

If angular momentum of a body increased by 200% its kinetic energy will increase by :

If momentum of an object is increased by 10%, then is kinetic energy will increase by

If linear momentum if increased by 50% then kinetic energy will be increased by

The momentum of a body is increased by 25%. The kinetic energy is increased by about

If the angular momentum of a body increases by 50%, its kinetic energy of rotation increases by

When momentum of a body increases by 200% its KE increases by

When momentum of a body increases by 200% its KE increases by

The momentum of a body is p and its kinetic energy is E. Its momentum becomes 2p. Its kinetic energy will be

If the angular momentum of any rotating body increases by 200% , then the increase in its kinetic energy

When mass and speed of a body is doubled the kinetic energy increases