Ethyl ester `overset(CH_(3)MgBr)underset("excess")rarrP,` the product P is

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Explanation

To solve the problem of determining the product P formed from the reaction of ethyl ester with excess CH₃MgBr (methylmagnesium bromide), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are ethyl ester (C₂H₅OCOCH₃) and excess CH₃MgBr. Ethyl ester can be represented as CH₃COOC₂H₅.

2. **Nucleophilic Attack**:
The Grignard reagent (CH₃MgBr) acts as a nucleophile and attacks the carbonyl carbon of the ethyl ester. This results in the formation of a tetrahedral intermediate.

\[ \text{CH}_3\text{COOC}_2\text{H}_5 + \text{CH}_3\text{MgBr} \rightarrow \text{Tetrahedral Intermediate} \]

3. **Formation of an Alcohol**:
The tetrahedral intermediate will collapse, leading to the formation of a ketone and the release of an alkoxide ion (C₂H₅O⁻). The ketone formed is acetone (CH₃COCH₃).

4. **Second Nucleophilic Attack**:
The alkoxide ion (C₂H₅O⁻) formed in the previous step can now react with another equivalent of CH₃MgBr. This leads to another nucleophilic attack on the carbonyl carbon of the acetone.

\[ \text{CH}_3\text{COCH}_3 + \text{C}_2\text{H}_5\text{O}^- \rightarrow \text{Second Tetrahedral Intermediate} \]

5. **Final Product Formation**:
The second tetrahedral intermediate will also collapse, leading to the formation of a tertiary alcohol. The final product P will be 2-methyl-2-propanol (tert-butyl alcohol).

\[ \text{Final Product: } \text{(CH}_3)_3\text{COH} \]

### Final Answer:
The product P formed from the reaction of ethyl ester with excess CH₃MgBr is **2-methyl-2-propanol (tert-butyl alcohol)**.

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