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In Young's double slit experiment, wavel...

In Young's double slit experiment, wavelength `lambda=5000Å` the distance between, the slits is `0.2mm` and the screen is at 200cm from the slits. The central maximum is at `x=0` The third maximum (Taking the central maximum as zeroth maximum) will be at x equal to

A

a.5.0 cm

B

b.0.5 cm

C

c.4.67 cm

D

d.1.5 cm

Text Solution

Verified by Experts

The correct Answer is:
D
For third maxima, `x=(3Dlamda)/(d)`
`=(3xx2xx5000xx10^(-10))/(0.2xx10^(-3))`
`=(6xx5xx10^(-7))/(2xx10^(-4))`
`=15mm=1.5`cm
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