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The magnetic field at P on the axis of a...

The magnetic field at P on the axis of a solenoid having 100 turn/m and carrrying a currennt of 5A is

A

`250mu_(0)`

B

`500sqrt(2)mu_(0)`

C

`500mu_(0)`

D

`250sqrt(2)mu_(0)`

Text Solution

Verified by Experts

The correct Answer is:
D
The magnetic field at P is
`B=(mu_(0)nI)/(2)(costheta+costheta)`
where n is number of turns, I the current, given, n=100,I=5A and `theta=45^(@)`
`B=(mu_(0)xx100xx5)/(2)xx(2)/(sqrt(2))`
`impliesB=250sqrt(2)mu_(0)`
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