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A longitudinal wave is represented by ...

A longitudinal wave is represented by
`x = x_(0) "sin"2pi("nt" - ("x")/(lambda))`
The maximum particle velocity will be four times the wave velocity if

A

`lamda=(nx_(0))/(4)`

B

`lamda=2pix_(0)`

C

`lamda=(pix_(0))/(2)`

D

`lamda=4pix_(0)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the given wave equation and derive the necessary relationships to find the condition under which the maximum particle velocity is four times the wave velocity. ### Step 1: Write down the wave equation The longitudinal wave is represented by the equation: \[ x = x_0 \sin(2\pi(nt - \frac{x}{\lambda})) \] ### Step 2: Identify parameters From the wave equation, we can identify: - \( x_0 \): Amplitude of the wave - \( n \): Frequency of the wave - \( \lambda \): Wavelength of the wave ### Step 3: Calculate the maximum particle velocity The particle velocity \( v_p \) can be calculated by differentiating the displacement \( x \) with respect to time \( t \): \[ v_p = \frac{dx}{dt} = \frac{d}{dt} \left( x_0 \sin(2\pi(nt - \frac{x}{\lambda})) \right) \] Using the chain rule: \[ v_p = x_0 \cdot 2\pi n \cos(2\pi(nt - \frac{x}{\lambda})) \] The maximum particle velocity \( v_{p,\text{max}} \) occurs when \( \cos(2\pi(nt - \frac{x}{\lambda})) = 1 \): \[ v_{p,\text{max}} = 2\pi n x_0 \] ### Step 4: Calculate the wave velocity The wave velocity \( v \) is given by the relationship: \[ v = n \lambda \] ### Step 5: Set up the condition According to the problem, the maximum particle velocity is four times the wave velocity: \[ v_{p,\text{max}} = 4v \] Substituting the expressions we found: \[ 2\pi n x_0 = 4(n \lambda) \] ### Step 6: Simplify the equation Dividing both sides by \( n \) (assuming \( n \neq 0 \)): \[ 2\pi x_0 = 4\lambda \] ### Step 7: Solve for \( \lambda \) Rearranging gives: \[ \lambda = \frac{\pi x_0}{2} \] ### Conclusion Thus, the condition under which the maximum particle velocity is four times the wave velocity is: \[ \lambda = \frac{\pi x_0}{2} \] ### Final Answer The correct option is (C) \( \frac{\pi x_0}{2} \). ---

To solve the problem step by step, we will analyze the given wave equation and derive the necessary relationships to find the condition under which the maximum particle velocity is four times the wave velocity. ### Step 1: Write down the wave equation The longitudinal wave is represented by the equation: \[ x = x_0 \sin(2\pi(nt - \frac{x}{\lambda})) \] ### Step 2: Identify parameters From the wave equation, we can identify: ...
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