The number of sodium atoms in 2 moles of sodium ferrocyanide is

Options

A. `12xx10^(23)`
B. `26xx10^(23)`
C. `34xx10^(23)`
D. `48xx10^(23)`

Explanation

To find the number of sodium atoms in 2 moles of sodium ferrocyanide (Na₄Fe(CN)₆), we can follow these steps:

### Step 1: Identify the formula of sodium ferrocyanide
The chemical formula for sodium ferrocyanide is Na₄Fe(CN)₆.

### Step 2: Determine the number of sodium atoms in one formula unit
From the formula Na₄Fe(CN)₆, we can see that there are 4 sodium (Na) atoms in one molecule of sodium ferrocyanide.

### Step 3: Calculate the number of sodium atoms in one mole
One mole of any substance contains Avogadro's number of entities, which is approximately \(6.022 \times 10^{23}\). Therefore, the number of sodium atoms in one mole of sodium ferrocyanide is:
\[ \text{Number of Na atoms in 1 mole} = 4 \times (6.022 \times 10^{23}) = 24.088 \times 10^{23} \text{ Na atoms} \]

### Step 4: Calculate the number of sodium atoms in 2 moles
To find the number of sodium atoms in 2 moles of sodium ferrocyanide, we multiply the number of sodium atoms in one mole by 2:
\[ \text{Number of Na atoms in 2 moles} = 2 \times (4 \times 6.022 \times 10^{23}) = 8 \times (6.022 \times 10^{23}) = 48.176 \times 10^{23} \text{ Na atoms} \]

### Step 5: Round the answer
Rounding \(48.176 \times 10^{23}\) gives us approximately \(48 \times 10^{23}\) sodium atoms.

### Final Answer
Thus, the number of sodium atoms in 2 moles of sodium ferrocyanide is:
\[ \text{Number of sodium atoms} = 48 \times 10^{23} \]