Assertion : At rest, radium is decayed into Radon and an `alpha`- particle. They both moves back to back of each other.
Reason : Splitting of radioactive particle is based on conservation of linear momentum.
Assertion : At rest, radium is decayed into Radon and an `alpha`- particle. They both moves back to back of each other.
Reason : Splitting of radioactive particle is based on conservation of linear momentum.
Reason : Splitting of radioactive particle is based on conservation of linear momentum.
A
a. If both assertion and reason are true and reason is the correct explanation of assertion.
B
If both assertion and reason are true but reason is not the correct explanation of assertion.
C
If assertion is true but reason is false
D
If both assertion and reason are false.
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Assertion: A particle of mass M at rest decays into two particles of masses m_(1) and m_(2) , having non-zero velocities will have ratio of the de-broglie wavelength unity. Reason: Here we cannot apply conservation of linear momentum.
Heavy radioactive nucleus decay through alpha- decay also. Consider a radioactive nucleus x. It spontaneously undergoes decay at rest resulting in the formation of a daughter nucleus y and the emission of an alpha- particle. The radioactive reaction can be given by x rarr y + alpha However , the nucleus y and the alpha- particle will be in motion. Then a natural question arises that what provides kinetic energy to the radioactive products. In fact, the difference of masses of the decaying nucleus and the decay products provides for the energy that is shared by the daughter nucleus and the alpha- particle as kinetic energy . We know that Einstein's mass-energy equivalence relation E = m c^(2) . Let m_(x), m_(y) and m_(alpha) be the masses of the parent nucleus x, the daughter nucleus y and alpha- particle respectively. Also the kinetic energy of alpha- particle just after the decay is E_(0) . Assuming all motion of to be non-relativistic. Which of the following is correct ?
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Heavy radioactive nucleus decay through alpha- decay also. Consider a radioactive nucleus x. It spontaneously undergoes decay at rest resulting in the formation of a daughter nucleus y and the emission of an alpha- particle. The radioactive reaction can be given by x rarr y + alpha However , the nucleus y and the alpha- particle will be in motion. Then a natural question arises that what provides kinetic energy to the radioactive products. In fact, the difference of masses of the decaying nucleus and the decay products provides for the energy that is shared by the daughter nucleus and the alpha- particle as kinetic energy . We know that Einstein's mass-energy equivalence relation E = m c^(2) . Let m_(x), m_(y) and m_(alpha) be the masses of the parent nucleus x, the daughter nucleus y and alpha- particle respectively. Also the kinetic energy of alpha- particle just after the decay is E_(0) . Assuming all motion of to be non-relativistic. Just after the decy , if the speed of alpha- particle is v, then the speed of the centre of mass of the system of the daughter nucleud y and the alpha- particle will be
When a particle is restricted to move along x-axis between x=0 and x=a , where alpha if of nenometer dimension, its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region, correspond to the formation of standing waves with nodes at its ends x=0 and x=a . The wavelength of this standing wave is related to the linear momentum p of the particle according to the de Broglie relation. The energy of the particle of mass m is related to its linear momentum as E=(p^2)/(2m) . Thus the energy of the particle can be denoted by a quantum number n taking values 1,2,3, ...( n=1 , called the ground state) corresponding to the number of loops in the standing wave. Use the model described above to answer the following three questions for a particle moving along the line from x=0 to x=alpha . Take h=6.6xx10^(-34)Js and e=1.6xx10^(-19) C. Q. If the mass of the particle is m=1.0xx10^(-30) kg and alpha=6.6nm , the energy of the particle in its ground state is closest to
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